would this trigger a notice if $foo is not defined?
if yes, then it would be different from the current behavior of the
ternary operator.
Couldn't believe it, thus I tested it myself
snip
Don't know, what you are talking about, but the notice _is_ the current
behaiour and therefore: No difference.
Sorry, I messed up that email. What I wanted to say:
If it accepts unset variable, then I could see usecases for it, but then it
would behave differently than the current ternary.
If it doesn't accept unset variable then it would in line with what we
have, but I don't see any usecase for it, because I would have to set it
before checking that it is falsely or not, in which case I would set it to
the default if not set already.
if no, then I would never use this.
I mean if I have to set the variable before the check, then I would put
the check into the assignment.
The main thought about it was
function foo ($bar = null) {
$bar = $bar ?: 'default';
}
If you wanted to enforce the 'default' value to be the default if no
argument passed, then you could use $bar = 'default' in the method
signature.
So I guess that you use that construct to handle when the argument is
passed, but it contains a falsely value ("0", array(), 0, etc.).
I agree that this can be useful in some cases.
I _always_ use 'null' as default
For me, it isn't always null, sometimes it is boolean true/false, or an
empty array.
- If you want to omit a parameter, but want to set one after that, you
don't need to look whats the default: It's 'null'
my IDE takes care of that problem for me.
- Ive often enough seen something like
function foo ($limit = 10) { /* code */ }
// Somewhere else
function bar ($limit = 50) { /* code */ $foo($limit); /* code */}
// Even somewhere else
bar();
same here.
