[Rails] Each returns just last array

As far as I can tell it's doing exactly what you asked it to do:

Let me explain....
1. First time through set @a to a new array containing the split of the
first element
2. Second time through replace @a with new array containing the split of
the second element
Enumerate the two elements contained in @a (i.e. [ 'myemail@second.com',
'My Name' ])
End of line....

Felipe Pieretti Umpierre wrote in post #1046832:

Maybe you wanted....
@a << for_each_one

Append split array to @a array. (i.e. an array of arrays).
The .each here would yield the two arrays contained within the outer
array.
I'm not sure if that's exactly what you wanted, but should point you in
the right direction.

Hello, what I want to do, the user gonna insert a string with right
combinations.

So, the user gonna put, the email[comma]name[semincolon]

This way, I need to split the semicolon, to have the array of strings,
after I need to split the comma, to have the name in a index, and the
email in another.

emails = params[ :email ][ :email ].split( ";" )
array = []

emails.each do |e|

foreach = e.split( ";" )
array << foreach

@a = array

end

["myemail@first.com,My Name"]
["myemail@second.com,My Name 2"]

But I can't access the index to split the comma.

Thank you

Okay, I thought my earlier explanation would be sufficient to help you
achieve your goal, but I'll try to explain further:

You are starting with this:

"myemail@first.com,My Name"; "myemail@second.com,My Name"

I can't guess what you want in your final result. There are multiple
ways to split and store this. So I'll explain what I would do in this
case, assuming I want to keep all the information in the original
string:

# Start by splitting the string at the semicolons:
arr1 = params[ :email ][ :email ].split( ";" )

# Result:
[ "myemail@first.com,My Name", "myemail@second.com,My Name" ]

# Declare an array to store the final data
emails = []

# Enumerate the array we split
arr1.each do |str|
# For each string in arr1 split at the comma
arr2 = str.split(",")

# Put the address and name in a hash (keyed by email address in this
case)
h[arr2[0]] = arr2[1]

# Append the hash to the final array
emails << h
end

# Final result:
[ { "myemail@first.com": "My Name" }, { "myemail@second.com", "My Name"
} ]

There might be some shortcut to the above procedure, but I wanted to
show all the individual steps to be clear what's happening.

As I said before, this is only one possible way to store the results
keeping all the original data. You'll have to decide what is best for
your particular case.