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Carlos Castillo |
at Jun 22, 2015 at 1:28 am
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⇧ | 
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AFAIK, it is inlined. Both in go 1.4 and 1.5.
Compiling
http://play.golang.org/p/HywIsDMfe0 with "-gcflags -m" set shows:
Go 1.5:
$ go build -gcflags -m
# nan
./nan.go:10: inlining call to math.IsNaN
./nan.go:10: math.IsNaN(x) escapes to heap
./nan.go:10: main ... argument does not escape
Go 1.4:
$ go build -gcflags -m
# nan
./nan.go:10: inlining call to math.IsNaN
./nan.go:10: main ... argument does not escape
What version of go are you running? How are you determining that it is not
being inlined?
On Saturday, June 20, 2015 at 5:28:34 AM UTC-7, webus...@gmail.com wrote:Thanks for the compiler flags. So it seems that math.IsNaN() is not
inlined. I copied the IsNaN function to my package and it was still not
in-lined. I just replaced the function call with f!=f.
Does anyone know what the rules are for a function to be in-lined or not?
It would seem IsNaN is a very simple function and would be ideal to be
in-lined.
On Friday, June 19, 2015 at 11:07:31 AM UTC-4, mkb wrote:If you are using the gc compiler, you can pass the compiler the “-m”
flag. With the go build command, add `-gcflags “-m”` to your
invocation.
On Fri, Jun 19, 2015 at 11:01 AM, wrote:I have some inner loops which are calling math.IsNaN() a very large number
of times. I looked at the code for IsNaN and it is just returning f != f. Is
this function call in-lined by the compiler?
Thanks
wu
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