Hmm...interesting...I've never looked at this report......my guess would
be that they are speculating that a disk read takes about 20 ms, so,
disk_reads/50 would give you seconds. Same idea for buffer_gets. If a
buffer get takes 2 ms, then buffer_gets/500 will yield seconds.
As to how accurate that conversion is, well, that depends on way too
much stuff to speculate on.....
-Mark
--
Mark J. Bobak
Senior Oracle Architect
ProQuest Information & Learning
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-----Original Message-----
From: oracle-l-bounce_at_freelists.org
On Behalf Of Srikanth Kalluri
Sent: Wednesday, March 01, 2006 6:11 PM
To: Oracle-L Freelists
Subject: RDA - Top SQL report
Hi,
The question is regarding (Remote Diagnostics Assistant; Metalink Note:
314422.1) Oracle Support provides to troubleshoot performance issues in
a database {RDA} and the calculation of the "Top SQL Report"
More specifically, I am curious how the following ratios are deemed
"Expected Respose Time (in Seconds)"
From v$sqlarea:
{ (disk_reads/executions)/50 }
{ (buffer_gets/executions)/500 }
Also, what is the significance of the numbers 50 and 500 respectively?
Queries used in the report:
select
sql_text,
executions,
disk_reads / decode(executions,0,1, executions) / 50 from v$sqlarea
where disk_reads / decode(executions,0,1, executions) / 50 > 100 order
by executions desc;
select
sql_text,
executions,
buffer_gets / decode(executions,0,1, executions) / 500 from v$sqlarea
where buffer_gets/ decode(executions,0,1, executions) / 500 > 100 order
by executions desc;
Thanks,
Sri
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