FAQ

Slafs <slafs.e at gmail.com> writes:
What i want to have is:
a "big" nested dictionary with 'g1' values as 1st level keys and a
dictionary of aggregates and "subgroups" in it....

I was looking for a solution that would let me do that kind of
grouping with variable lists of 2) and 3) i.e. having also 'g3' as
grouping element so the 'g2' dicts could also have their own
"subgroup" and be even more nested then.
I was trying something with itertools.groupby and updating nested
dicts, but as i was writing the code it started to feel too verbose to
me :/

Do You have any hints maybe? because i'm kind of stucked :/
I'm not sure I understood the problem and it would help if you gave
sample data with the deeper nesting that you describe. But the
following messy code matches the sample that you did give:

from pprint import pprint
from itertools import groupby

x1 = [ { 'g1' : 1, 'g2' : 8, 's_v1' : 5.0, 's_v2' : 3.5 },
{ 'g1' : 1, 'g2' : 9, 's_v1' : 2.0, 's_v2' : 3.0 },
{ 'g1' : 2, 'g2' : 8, 's_v1' : 6.0, 's_v2' : 8.0}
]
x2 = ['g1', 'g2']
x3 = ['s_v1', 's_v2']

def agg(xdata, group_keys, agg_keys):
if not group_keys:
return {}
k0, ks = group_keys[0], group_keys[1:]
r = {}
def gk(d): return d[k0]
for k, g in groupby(sorted(xdata, key=gk), gk):
gs = list(g)
aggs = dict((ak,sum(d[ak] for d in gs)) for ak in agg_keys)
r[k] = aggs
if ks:
r[k][ks[0]] = agg(gs,group_keys[1:], agg_keys)
return r

pprint (agg(x1, x2, x3))

Search Discussions

Discussion Posts

Previous

Follow ups

Related Discussions

Discussion Navigation
viewthread | post
posts ‹ prev | 3 of 6 | next ›
Discussion Overview
grouppython-list @
categoriespython
postedFeb 4, '11 at 11:14p
activeFeb 7, '11 at 4:52p
posts6
users5
websitepython.org

People

Translate

site design / logo © 2022 Grokbase