FAQ
"Mahesh" advised:
Timing it out will probably solve it.

Thanks.

Follow-on question regarding implementing a timeout for use by urllib2. I am guessing the simplest way to do this is via socket.setdefaulttimeout(), but I am not sure if this sets a global parameter, and if so, whether it might be reset via instantiations of urllib, urllib2, httplib, etc. I assume socket and the timeout parameter is in the global namespace and that I can just reset it at will for application to all the socket module 'users'. Is that right?

(TIA)


[experimenting]
import urllib2plus
urllib2plus.setSocketTimeOut(1)
urllib2plus.urlopen('http://zomething.com')
Traceback (most recent call last):
File "<pyshell#52>", line 1, in -toplevel-
urllib2plus.urlopen('http://zomething.com')
File "C:\Python24\lib\urllib2plus.py", line 130, in urlopen
return _opener.open(url, data)
File "C:\Python24\lib\urllib2plus.py", line 361, in open
response = self._open(req, data)
File "C:\Python24\lib\urllib2plus.py", line 379, in _open
'_open', req)
File "C:\Python24\lib\urllib2plus.py", line 340, in _call_chain
result = func(*args)
File "C:\Python24\lib\urllib2plus.py", line 1024, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "C:\Python24\lib\urllib2plus.py", line 999, in do_open
raise URLError(err)
URLError: <urlopen error timed out>
urllib2plus.setSocketTimeOut(10)
urllib2plus.urlopen('http://zomething.com')
<addinfourl at 12449152 whose fp = <socket._fileobject object at 0x00BE1340>>
import socket
socket.setdefaulttimeout(0)
urllib2plus.urlopen('http://zomething.com')
Traceback (most recent call last):
File "<pyshell#60>", line 1, in -toplevel-
urllib2plus.urlopen('http://zomething.com')
File "C:\Python24\lib\urllib2plus.py", line 130, in urlopen
return _opener.open(url, data)
File "C:\Python24\lib\urllib2plus.py", line 361, in open
response = self._open(req, data)
File "C:\Python24\lib\urllib2plus.py", line 379, in _open
'_open', req)
File "C:\Python24\lib\urllib2plus.py", line 340, in _call_chain
result = func(*args)
File "C:\Python24\lib\urllib2plus.py", line 1024, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "C:\Python24\lib\urllib2plus.py", line 999, in do_open
raise URLError(err)
URLError: <urlopen error (10035, 'The socket operation could not complete without blocking')>
socket.setdefaulttimeout(1)
urllib2plus.urlopen('http://zomething.com')
<addinfourl at 12449992 whose fp = <socket._fileobject object at 0x00BE1420>>

Search Discussions

Discussion Posts

Previous

Follow ups

Related Discussions

Discussion Navigation
viewthread | post
posts ‹ prev | 3 of 4 | next ›
Discussion Overview
grouppython-list @
categoriespython
postedJun 6, '05 at 3:01a
activeJun 6, '05 at 3:20p
posts4
users2
websitepython.org

2 users in discussion

EP: 2 posts Mahesh: 2 posts

People

Translate

site design / logo © 2018 Grokbase