Leif K-Brooks wrote:

Chris Green wrote:
I've done a bit of searching in the language reference and a couple
pages referring the behavior of super() but I can't find any
discussion of why super needs the name of the class as an argument.

Think about it. In this code:

class A(object):
def do_stuff(self):
print "A is doing stuff now."

class B(A):
def do_stuff(self):
super(B, self).do_stuff()
print "B is doing stuff now."

class C(B):
def do_stuff(self):
super(C, self).do_stuff()
print "C is doing stuff now."

How would Python know that B should call C's do_stuff() method instead
of its own if there was no class argument? The self argument would be
exactly the same when C called super() as when B called it. There has
been some talk of making super into a language keyword instead of a
type, though; that would eliminate the need to even pass in self.
What's the going argument against it? Makes sense to me.

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grouppython-list @
postedOct 15, '04 at 2:52p
activeOct 16, '04 at 10:11a



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