FAQ

On 02/10/2009 02:07:23 PM, Karl O. Pinc wrote:
On 02/10/2009 10:20:51 AM, Brian Canty wrote:
I was wondering if anyone knows of any command you can use to find
out
who is subscribed to all mailman lists.
Somehow the "cut" command got mangled. Should be:

list_lists \
tail -n +2 \
awk '{print $1;}' \
xargs -n 1 bash -c 'list_members $0 | xargs -n 1 echo $0:' \
grep foo at example.com \
cut -d : -f 1
Gets you all the lists that foo at example.com is subscribed to.

Karl <kop at meme.com>
Free Software: "You don't pay back, you pay forward."
-- Robert A. Heinlein

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groupmailman-users @
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postedFeb 10, '09 at 4:20p
activeFeb 12, '09 at 4:49a
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