Ok, aha moment I hope ...
On Friday, August 28, 2015 at 12:31:55 AM UTC-7, Jesse McNelis wrote:

There is no spooky at a distance action. The decision about whether a
type implements an interface is based on the type's method set.

That has been my understanding. But, it is not quite complete, though in
hindsight the missing bit does seem obvious.

That "decision of whether X implements Y" is evaluated only at the point of
assignment. That makes it sound like a run-time evaluation, but Go
apparently evaluates it at compile-time and at every assignment that
depends on whether X implements Y. Different assignments -- pointer or
value -- can result in different evaluations of whether X implements Y.
Absent an assignment, there is simply no relationship between X and Y -- Go
has no 'extends' or 'implements'.

So, no spooky action at a distance - the variable assignment is the action.

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postedAug 27, '15 at 10:48p
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