Grokbase Groups R r-help June 2016
FAQ
Hi All,


I need to build a binary vector made of a set of dichotomous variables.


What I have so far is:


-- cut --


ds_example <-
   structure(
     list(
       year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
       year2014 = c(0,
                    0, 1, 1, 0, 0, 1, 1),
       year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
     ),
     .Names = c("year2013",
                "year2014", "year2015"),
     row.names = c(NA, 8L),
     class = "data.frame"
   )


attach(ds_example)
base <- 1000
binary_vector <- base + year2013 * 100 + year2014 * 10 + year2015
detach(ds_example)


binary_vector


ds_example <- cbind(ds_example, binary_vector)


varlist <- c("year2013", "year2014", "year2015")


base <- 10^length(varlist)


binary_vector <- NULL


for (i in 1:3) {
   binary_vector <-
    base +
    ds_example [[varlist[i]]] * base / (10 ^ i)
}


ds_example <- cbind(ds_example, binary_vector)


message("Wrong result!")
ds_example


-- cut --


How do I get vectors like 1000 1001 1011 1111 1100 1101 1110 1010 for
each case?


Is there a better approach than mine?


Kind regards


Georg

Search Discussions

  • Tom Wright at Jun 16, 2016 at 2:13 pm
    Does this do what you want?


    as.numeric(with(ds_example,paste(1,year2013,year2014,year2015,sep='')))

    On Thu, Jun 16, 2016 at 8:57 AM, wrote:
    Hi All,

    I need to build a binary vector made of a set of dichotomous variables.

    What I have so far is:

    -- cut --

    ds_example <-
    structure(
    list(
    year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
    year2014 = c(0,
    0, 1, 1, 0, 0, 1, 1),
    year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
    ),
    .Names = c("year2013",
    "year2014", "year2015"),
    row.names = c(NA, 8L),
    class = "data.frame"
    )

    attach(ds_example)
    base <- 1000
    binary_vector <- base + year2013 * 100 + year2014 * 10 + year2015
    detach(ds_example)

    binary_vector

    ds_example <- cbind(ds_example, binary_vector)

    varlist <- c("year2013", "year2014", "year2015")

    base <- 10^length(varlist)

    binary_vector <- NULL

    for (i in 1:3) {
    binary_vector <-
    base +
    ds_example [[varlist[i]]] * base / (10 ^ i)
    }

    ds_example <- cbind(ds_example, binary_vector)

    message("Wrong result!")
    ds_example

    -- cut --

    How do I get vectors like 1000 1001 1011 1111 1100 1101 1110 1010 for
    each case?

    Is there a better approach than mine?

    Kind regards

    Georg

    ______________________________________________
    R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
    https://stat.ethz.ch/mailman/listinfo/r-help
    PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
    and provide commented, minimal, self-contained, reproducible code.
  • G Maubach at Jun 17, 2016 at 7:19 am
    Hi Tom,

    thanks for your reply.

    Yes, that's exactly what I am looking for. I did not know about the automatic type conversion in R.

    #-- cut --
    ds_example <-
    structure(
    list(
    year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
    year2014 = c(0,
    0, 1, 1, 0, 0, 1, 1),
    year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
    ),
    .Names = c("year2013",
    "year2014", "year2015"),
    row.names = c(NA, 8L),
    class = "data.frame"
    )

    #-- Proposal: works!
    as.numeric(with(ds_example,paste(1,year2013,year2014,year2015,sep='')))

    # I store my know-how about R in functions for later use.

    #--? Putting it in a function - does not work!
    t_make_binary_vector <- function(dataset,
    input_variables,
    output_variable = "binary_vector") {
    dataset[output_variable] <- "1"
    print(dataset[output_variable])

    for (variable in input_variables) {
    print(variable)
    dataset[output_variable] <- paste(dataset[output_variable],
    dataset[variable],
    sep='')
    }

    # print(dataset[output_variable])

    dataset[output_variable] <- as.integer(dataset[output_variable])

    return(dataset)
    }

    t_make_binary_vector(dataset = ds_example,
    input_variables = c("year2013", "year2014", "year2015"),
    output_variable = "binary_vector")


    #-- Doesn't work either.
    t_make_binary_vector <- function(dataset,
    input_variables,
    output_variable = "binary_vector") {
    dataset[output_variable] <- as.integer(paste(1, dataset[ , input_variables], sep = ''))

    return(dataset)
    }

    t_make_binary_vector(dataset = ds_example,
    input_variables = c("year2013", "year2014", "year2015"),
    output_variable = "binary_vector")

    #-- cut --

    Why is R taking the parameter value itself to paste it together instead of referencing the variable within the dataset?

    What did I get wrong about R? How can I fix it?

    Kind regards

    Georg

    Gesendet: Donnerstag, 16. Juni 2016 um 16:13 Uhr
    Von: "Tom Wright" <tom@maladmin.com>
    An: G.Maubach at weinwolf.de
    Cc: "R. Help" <r-help@r-project.org>
    Betreff: Re: [R] Building a binary vector out of dichotomous variables

    Does this do what you want?

    as.numeric(with(ds_example,paste(1,year2013,year2014,year2015,sep='')))
    On Thu, Jun 16, 2016 at 8:57 AM, wrote:
    Hi All,

    I need to build a binary vector made of a set of dichotomous variables.

    What I have so far is:

    -- cut --

    ds_example <-
    structure(
    list(
    year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
    year2014 = c(0,
    0, 1, 1, 0, 0, 1, 1),
    year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
    ),
    .Names = c("year2013",
    "year2014", "year2015"),
    row.names = c(NA, 8L),
    class = "data.frame"
    )

    attach(ds_example)
    base <- 1000
    binary_vector <- base + year2013 * 100 + year2014 * 10 + year2015
    detach(ds_example)

    binary_vector

    ds_example <- cbind(ds_example, binary_vector)

    varlist <- c("year2013", "year2014", "year2015")

    base <- 10^length(varlist)

    binary_vector <- NULL

    for (i in 1:3) {
    binary_vector <-
    base +
    ds_example [[varlist[i]]] * base / (10 ^ i)
    }

    ds_example <- cbind(ds_example, binary_vector)

    message("Wrong result!")
    ds_example

    -- cut --

    How do I get vectors like 1000 1001 1011 1111 1100 1101 1110 1010 for
    each case?

    Is there a better approach than mine?

    Kind regards

    Georg

    ______________________________________________
    R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
    https://stat.ethz.ch/mailman/listinfo/r-help
    PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
    and provide commented, minimal, self-contained, reproducible code.
    ______________________________________________
    R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
    https://stat.ethz.ch/mailman/listinfo/r-help
    PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
    and provide commented, minimal, self-contained, reproducible code.
  • PIKAL Petr at Jun 17, 2016 at 8:34 am
    Hi


    Your approach seems to me rather tricky


    This should work


    make_bv <- function(dataset, input_variables) {


    dd <- which(names(dataset) %in% input_variables)
    dat<-dataset[,dd]
    x <- 10^(ncol(dat):0)
    result <- cbind(dataset, binary_vec=x[1]+rowSums(sweep(dat, 2, x[-1], "*")))
    result}


    make_bv(dataset = ds_example, input_variables = c("year2013", "year2015"))


    Cheers
    Petr

    -----Original Message-----
    From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of
    G.Maubach at gmx.de
    Sent: Friday, June 17, 2016 9:19 AM
    To: r-help at r-project.org
    Subject: [R] Fw: Aw: Re: Building a binary vector out of dichotomous variables
    Hi Tom,

    thanks for your reply.

    Yes, that's exactly what I am looking for. I did not know about the
    automatic type conversion in R.
    #-- cut --
    ds_example <-
    structure(
    list(
    year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
    year2014 = c(0,
    0, 1, 1, 0, 0, 1, 1),
    year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
    ),
    .Names = c("year2013",
    "year2014", "year2015"),
    row.names = c(NA, 8L),
    class = "data.frame"
    )

    #-- Proposal: works!
    as.numeric(with(ds_example,paste(1,year2013,year2014,year2015,sep=''))
    )

    # I store my know-how about R in functions for later use.

    #--? Putting it in a function - does not work!
    t_make_binary_vector <- function(dataset,
    input_variables,
    output_variable = "binary_vector") {
    dataset[output_variable] <- "1"
    print(dataset[output_variable])

    for (variable in input_variables) {
    print(variable)
    dataset[output_variable] <- paste(dataset[output_variable],
    dataset[variable],
    sep='')
    }

    # print(dataset[output_variable])

    dataset[output_variable] <- as.integer(dataset[output_variable])

    return(dataset)
    }

    t_make_binary_vector(dataset = ds_example,
    input_variables = c("year2013", "year2014", "year2015"),
    output_variable = "binary_vector")


    #-- Doesn't work either.
    t_make_binary_vector <- function(dataset,
    input_variables,
    output_variable = "binary_vector") {
    dataset[output_variable] <- as.integer(paste(1, dataset[ ,
    input_variables], sep = ''))

    return(dataset)
    }

    t_make_binary_vector(dataset = ds_example,
    input_variables = c("year2013", "year2014", "year2015"),
    output_variable = "binary_vector")

    #-- cut --

    Why is R taking the parameter value itself to paste it together instead of
    referencing the variable within the dataset?
    What did I get wrong about R? How can I fix it?

    Kind regards

    Georg

    Gesendet: Donnerstag, 16. Juni 2016 um 16:13 Uhr
    Von: "Tom Wright" <tom@maladmin.com>
    An: G.Maubach at weinwolf.de
    Cc: "R. Help" <r-help@r-project.org>
    Betreff: Re: [R] Building a binary vector out of dichotomous
    variables

    Does this do what you want?

    as.numeric(with(ds_example,paste(1,year2013,year2014,year2015,sep=''
    )))
    On Thu, Jun 16, 2016 at 8:57 AM, wrote:
    Hi All,

    I need to build a binary vector made of a set of dichotomous variables.

    What I have so far is:

    -- cut --

    ds_example <-
    structure(
    list(
    year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
    year2014 = c(0,
    0, 1, 1, 0, 0, 1, 1),
    year2015 = c(0, 1, 1, 1, 0, 1, 0, 0)
    ),
    .Names = c("year2013",
    "year2014", "year2015"),
    row.names = c(NA, 8L),
    class = "data.frame"
    )

    attach(ds_example)
    base <- 1000
    binary_vector <- base + year2013 * 100 + year2014 * 10 + year2015
    detach(ds_example)

    binary_vector

    ds_example <- cbind(ds_example, binary_vector)

    varlist <- c("year2013", "year2014", "year2015")

    base <- 10^length(varlist)

    binary_vector <- NULL

    for (i in 1:3) {
    binary_vector <-
    base +
    ds_example [[varlist[i]]] * base / (10 ^ i) }

    ds_example <- cbind(ds_example, binary_vector)

    message("Wrong result!")
    ds_example

    -- cut --

    How do I get vectors like 1000 1001 1011 1111 1100 1101 1110 1010
    for each case?

    Is there a better approach than mine?

    Kind regards

    Georg

    ______________________________________________
    R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
    https://stat.ethz.ch/mailman/listinfo/r-help
    PLEASE do read the posting guide
    http://www.R-project.org/posting-guide.html
    and provide commented, minimal, self-contained, reproducible code.
    ______________________________________________
    R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
    https://stat.ethz.ch/mailman/listinfo/r-help
    PLEASE do read the posting guide
    http://www.R-project.org/posting-guide.html
    and provide commented, minimal, self-contained, reproducible code.
    ______________________________________________
    R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
    https://stat.ethz.ch/mailman/listinfo/r-help
    PLEASE do read the posting guide http://www.R-project.org/posting-
    guide.html
    and provide commented, minimal, self-contained, reproducible code.

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