Grokbase Groups R r-help October 2015
FAQ
If you want to use the numbers you gave a the index into the matrix, then
you can create a matrix with the values and then index into 'm'. I don't
see a '4' in the output example you gave using your index values:

m <- structure(c(0L, 0L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
+ 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 0L, 0L, 0L, 2L, 2L, 2L, 2L,
+ 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 0L,
+ 0L, 0L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L,
+ 3L, 3L, 3L, 3L, 3L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 4L, 4L, 4L,
+ 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 0L, 0L, 0L, 0L, 0L,
+ 0L, 0L, 0L, 0L, 0L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L,
+ 5L), .Dim = c(22L, 5L))
# create index matrix
indx <- matrix(c(4, 1,
+ 5, 2,
+ 6, 3,
+ 7, 1,
+ 8, 2,
+ 9, 3,
+ 10, 1,
+ 11, 2,
+ 12, 3), ncol = 2, byrow = TRUE)

m
       [,1] [,2] [,3] [,4] [,5]
  [1,] 0 0 0 0 0
  [2,] 0 0 0 0 0
  [3,] 0 0 0 0 0
  [4,] 1 2 3 0 0
  [5,] 1 2 3 0 0
  [6,] 1 2 3 0 0
  [7,] 1 2 3 0 0
  [8,] 1 2 3 0 0
  [9,] 1 2 3 4 0
[10,] 1 2 3 4 0
[11,] 1 2 3 4 5
[12,] 1 2 3 4 5
[13,] 1 2 3 4 5
[14,] 1 2 3 4 5
[15,] 1 2 3 4 5
[16,] 1 2 3 4 5
[17,] 1 2 3 4 5
[18,] 1 2 3 4 5
[19,] 1 2 3 4 5
[20,] 1 2 3 4 5
[21,] 1 2 3 4 5
[22,] 1 2 3 4 5
indx
       [,1] [,2]
  [1,] 4 1
  [2,] 5 2
  [3,] 6 3
  [4,] 7 1
  [5,] 8 2
  [6,] 9 3
  [7,] 10 1
  [8,] 11 2
  [9,] 12 3
m[indx]
[1] 1 2 3 1 2 3 1 2 3




Jim Holtman
Data Munger Guru


What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.


On Tue, Oct 27, 2015 at 2:43 PM, Jorge I Velez wrote:

Dear R-help,

I am working with a matrix "m" from which I would like to extract some
elements. An toy example is as follows:

## input matrix
m <- structure(c(0L, 0L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 0L, 0L, 0L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 0L,
0L, 0L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L,
3L, 3L, 3L, 3L, 3L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 0L, 0L, 0L, 0L, 0L,
0L, 0L, 0L, 0L, 0L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L,
5L), .Dim = c(22L, 5L))

R> m
# [,1] [,2] [,3] [,4] [,5]
# [1,] 0 0 0 0 0
# [2,] 0 0 0 0 0
# [3,] 0 0 0 0 0
# [4,] 1 2 3 0 0
# [5,] 1 2 3 0 0
# [6,] 1 2 3 0 0
# [7,] 1 2 3 0 0
# [8,] 1 2 3 0 0
# [9,] 1 2 3 4 0
# [10,] 1 2 3 4 0
# [11,] 1 2 3 4 5
# [12,] 1 2 3 4 5
From "m", I would like to extract the entries
4, 1
5, 2
6, 3
7, 1
8, 2
9, 3
10, 1
11, 2
12, 3

so at the end of applying a function "f" to "m" I get

1, 2, 3, 1, 2, 3, 4, 1, 2, 3


Basically the idea is to extract the diagonal elements until a zero is
found.

In the real problem the dimensions of "m" are much bigger, but this smaller
version of "m" illustrate what needs to be done.

I would greatly appreciate any ideas on how to do this.

Thanks in advance,
Jorge Velez.-

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