Grokbase Groups R r-help October 2015
FAQ

Is this what you want::


a <- 1
b <- 2
# get current objects
x <- ls()
# create list of values
my_list <- lapply(x, get)
# now add the names
names(my_list) <- x
my_list # print values
$a
[1] 1
$b
[1] 2






Jim Holtman
Data Munger Guru


What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.


On Sun, Oct 18, 2015 at 3:16 PM, wrote:

Hello,

I'm not sure I understand, but something like this?

a <- 5
get("a")

See ?get
Hope this helps,

Rui Barradas


Citando Christian Hoffmann <christian@echoffmann.ch>:
This may seem trivial:

ls() gives me names of variables as a character vector. How can I print
the values 'behind' those character values:

ls()
"a"
a
[1] 5

How can I do e.g. print("unknown"(ls())) and get the variable values in
my current environment?

--
Christian W. Hoffmann
CH - 8915 Hausen am Albis, Schweiz
Rigiblickstrasse 15 b, Tel.+41-44-7640853
mailto: christian at echoffmann.ch
home: www.echoffmann.ch[1]

______________________________________________
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minimal, self-contained, reproducible code.


Liga??es:
---------
[1] http://www.echoffmann.ch

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______________________________________________
R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

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